Write the equation which you have BUT you have omitted the yield sign and and + signs. No way to know the difference between reactants and products.
Convert 100.0 g AgCl to mols.
Using the coefficients in the balanced equation, convert mols AgCl to mols Ag.
Convert mols Ag to grams Ag by grams = mols x molar mass.
Substitute in the earlier problem for the percent yield and solve for the actual amount. Post your work if you get stuck.
One method for reclaiming silver metal from silver chloride results in a 94.6%
yield. Calculate the actual mass of silver that can be produced in this reaction
if 100.0 g of silver chloride is converted to silver metal.
2AgCl(s) y 2Ag(s) . Cl2(g)
5 answers
hgj
2AgCl(s) y 2Ag(s) 1 Cl2(g)
100.0 g AgCl * 1 mol AgCl/143.5 g AgCl * 2 mol Ag/2 mol AgCl * 108 g Ag/1 mol = 75.3 g Ag, mass of Ag(s) reclaimed = 0.946 * 75.3 g Ag = 71.2 g Ag. Hope it helps :)
poop
2 answers