To determine which of the given points is part of the solution set for the inequality \( y \leq \frac{2}{5}x + 1 \), we need to check which points satisfy the inequality.
First, let's write the equation of the line for the boundary of the inequality:
\[ y = \frac{2}{5}x + 1 \]
Now we will evaluate each point in relation to this equation.
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Point (10, 4): \[ y = \frac{2}{5}(10) + 1 = 4 + 1 = 5 \] Here, \( 4 \leq 5 \) is true. So, (10, 4) satisfies the inequality.
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Point (10, 5.5): \[ y = \frac{2}{5}(10) + 1 = 4 + 1 = 5 \] Here, \( 5.5 \leq 5 \) is false. So, (10, 5.5) does not satisfy the inequality.
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Point (-10, 6): \[ y = \frac{2}{5}(-10) + 1 = -4 + 1 = -3 \] Here, \( 6 \leq -3 \) is false. So, (-10, 6) does not satisfy the inequality.
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Point (10, 6): \[ y = \frac{2}{5}(10) + 1 = 4 + 1 = 5 \] Here, \( 6 \leq 5 \) is false. So, (10, 6) does not satisfy the inequality.
Based on this evaluation, the only point that is part of the solution set is:
(10, 4).