V = k Q/r where Q = 6* 1.6*10^-19 Coulombs
= 9*10^9 (6)(1.6*10^-19)/10^-10
= 86.4 * 10^(9+10-19)
= 86.4
Show that the electric potential of carbon nucleus of equivalent charge +6e at a distance of 1x10^-10 m from a carbon nucleus with constant k of 9 x 10^9 is 86.4V
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2 answers
remember E = k Q /r^2
V = -integral of E from infinity to r= work done to bring 1 C charge in from infinity , force opposite to motion
V = -k Q (-1/r) ......at r - at infinity
= -k Q [ -1/r +1/infinity]
= k Q / r
V = -integral of E from infinity to r= work done to bring 1 C charge in from infinity , force opposite to motion
V = -k Q (-1/r) ......at r - at infinity
= -k Q [ -1/r +1/infinity]
= k Q / r
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