K = 39.1 or thereabouts
Cl = 35.4 about
O = 3*16 = 48 about.
You can look up these numbers and add them.
Show that one mole of KCLO3 contains 122.55 grams.
2 KCLO3(s)->2 KCL(s) + 3 O2(g)
1 answer
2 KCLO3(s)->2 KCL(s) + 3 O2(g)
1 answer
1 answer
1 answer
1 answer
3 answers