Show how many solutions are in the solution set for the equation 3xexponent2 =21 .(1 point)

Question

Responses

two
two

infinitely many
infinitely many

one
one

zero

Answer 1

To solve the equation \( 3x^2 = 21 \), we can first simplify it.

1. Divide both sides by 3:

   \[ x^2 = 7 \]

2. Now, take the square root of both sides:

   \[ x = \sqrt{7} \quad \text{or} \quad x = -\sqrt{7} \]

This means there are two solutions:

• \( x = \sqrt{7} \)
• \( x = -\sqrt{7} \)

Therefore, the number of solutions in the solution set is two.