Show how many solutions are in the solution set for the equation 3xexponent2 =21 .(1 point)

Responses

two
two

infinitely many
infinitely many

one
one

zero

1 answer

To solve the equation \( 3x^2 = 21 \), we can first simplify it.

  1. Divide both sides by 3:

    \[ x^2 = 7 \]

  2. Now, take the square root of both sides:

    \[ x = \sqrt{7} \quad \text{or} \quad x = -\sqrt{7} \]

This means there are two solutions:

  • \( x = \sqrt{7} \)
  • \( x = -\sqrt{7} \)

Therefore, the number of solutions in the solution set is two.