To determine if \( x = -3 \) is a solution to the quadratic equation \( -3x^2 - 9x = 0 \), let's substitute \( x = -3 \) into the equation:
\[ -3(-3)^2 - 9(-3) = 0 \]
First, calculate \( (-3)^2 \):
\[ (-3)^2 = 9 \]
Now substitute this back into the equation:
\[ -3(9) - 9(-3) = 0 \]
Calculating \( -3(9) \):
\[ -27 \]
Calculating \( -9(-3) \):
\[ 27 \]
Now combine these results:
\[ -27 + 27 = 0 \]
So, the equation simplifies to:
\[ 0 = 0 \]
This is a true statement.
Therefore, the correct explanation that demonstrates the reasoning is:
Yes, \( x = -3 \) is a solution because substituting it back into the equation results in the following: \[ -3(-3)^2 - 9(-3) = 0 \quad \Rightarrow \quad 0 = 0 \quad \text{True} \]
This confirms that yes, \( x = -3 \) is a solution.