Asked by Anon
Set up, but do not evalute, to find the area of the region bounded by the graphs of y=10x-x^2, y=2x and x=10. Sketch the graph
Answers
Answered by
mathhelper
I would do the sketch first.
A simple quick solution will show that the parabola cuts the line at
(0,) and (8,16) , so you have a nice inclosed region form (0,0) to (8,16) where
the parabola is above the straight line, and another region from
x = 8 to x = 10 with the straight line above the parabola
so area
= ∫ (10x - x^2 - 2x) dx from 0 to 8 + ∫ (2x - 10x + x^2) dx from 8 to 10
there is your setup, now your turn.
A simple quick solution will show that the parabola cuts the line at
(0,) and (8,16) , so you have a nice inclosed region form (0,0) to (8,16) where
the parabola is above the straight line, and another region from
x = 8 to x = 10 with the straight line above the parabola
so area
= ∫ (10x - x^2 - 2x) dx from 0 to 8 + ∫ (2x - 10x + x^2) dx from 8 to 10
there is your setup, now your turn.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.