To determine which of the ordered pairs is part of the solution set for the equation \( y = 4x + 2 \), we can substitute \( x = 3 \) into the equation and calculate the corresponding value of \( y \).
Substituting \( x = 3 \) into the equation:
\[ y = 4(3) + 2 \] \[ y = 12 + 2 \] \[ y = 14 \]
Now, we check the ordered pairs:
A) \( (3, 45) \) → \( y \neq 14 \)
B) \( (3, 14) \) → \( y = 14 \) (this is a solution)
C) \( (3, 12) \) → \( y \neq 14 \)
D) \( (3, 7) \) → \( y \neq 14 \)
The correct option is:
B) (3, 14)