To determine which of the ordered pairs is part of the solution set for the equation \( y = 4x + 2 \), we need to substitute the x-value from each pair into the equation and see if the resulting y-value matches the y-value from the ordered pair.
The equation is \( y = 4x + 2 \).
Let’s check each ordered pair:
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For (3, 14): \[ y = 4(3) + 2 = 12 + 2 = 14 \] Match! So (3, 14) is a solution.
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For (3, 45): \[ y = 4(3) + 2 = 12 + 2 = 14 \] No match! (3, 45) is not a solution.
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For (3, 12): \[ y = 4(3) + 2 = 12 + 2 = 14 \] No match! (3, 12) is not a solution.
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For (3, 7): \[ y = 4(3) + 2 = 12 + 2 = 14 \] No match! (3, 7) is not a solution.
The only ordered pair that is part of the solution set for the equation \( y = 4x + 2 \) is (3, 14).
1 answer