To determine which ordered pair is part of the solution set for the equation \( y = 4x + 2 \), we can substitute \( x = 3 \) into the equation and solve for \( y \):
\[ y = 4(3) + 2 \] \[ y = 12 + 2 \] \[ y = 14 \]
Now we can check the options:
- A) \( (3, 34) \) → \( y = 34 \) (not a solution)
- B) \( (3, 14) \) → \( y = 14 \) (this is a solution)
- C) \( (3, 12) \) → \( y = 12 \) (not a solution)
- D) \( (3, 7) \) → \( y = 7 \) (not a solution)
The correct option is B) (3, 14).