To determine the ordered pairs that are solutions for the equation \( y = 4x + 2 \), you can substitute values for \( x \) and calculate the corresponding \( y \) values.
Let's find a few ordered pairs by substituting values for \( x \):
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If \( x = 0 \): \[ y = 4(0) + 2 = 2 \quad \Rightarrow \quad (0, 2) \]
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If \( x = 1 \): \[ y = 4(1) + 2 = 6 \quad \Rightarrow \quad (1, 6) \]
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If \( x = -1 \): \[ y = 4(-1) + 2 = -2 \quad \Rightarrow \quad (-1, -2) \]
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If \( x = 2 \): \[ y = 4(2) + 2 = 10 \quad \Rightarrow \quad (2, 10) \]
Now we have the following ordered pairs that are solutions to the equation \( y = 4x + 2 \):
- \( (0, 2) \)
- \( (1, 6) \)
- \( (-1, -2) \)
- \( (2, 10) \)
If you have specific ordered pairs to evaluate, you can apply this method to check if they satisfy the equation \( y = 4x + 2 \). Please provide the options of ordered pairs, and I can help you determine which ones are solutions to the given equation.
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