The net force acting on the trailer can be calculated by subtracting the frictional force from the force applied by Scout:
Net force = Force applied - Frictional force
= 8 N - 3 N
= 5 N
Using Newton's second law of motion, which states that the net force acting on an object is equal to the product of its mass and acceleration:
Net force = mass × acceleration
Rearranging this equation to solve for acceleration:
acceleration = Net force / mass
= 5 N / 10 kg
= 0.5 m/s^2
Therefore, the trailer's acceleration will be 0.5 (m/s^2).
The correct answer is C. 0.5 (m/s^2).
Scout is trying to push a 10 kg trailer across a gravel Road she’s pushing with a force of 8 N of force, but the gravel is providing a frictional force of 3 N in the opposite direction. What will be the trailers acceleration
A. 2 (m/s^2)
B. 7 (m/s^2)
C. 0.5 (m/s^2)
D. 1.1 (m/s^2)
1 answer
4 answers