scientists use the formula d=0.099m^(9/10) to give the drinking rate, d litres per day, for a mammal with mass m kilograms.
A) rewrite the equation using radicals
B) Determine the drinking rate of each mammal.
i) a 35kg dog
ii) a 520kg moose
iii) a 28g mouse
my answers:
A) radicals: 10√m^9
B) i) 10√35^9 = 2.45 L/day
ii) 10√520^9 =
I got 278230 L/day but my textbook answer says 27.54 L/day. I really don't understand why.
iii) 28/100 = 0.028kg
10√0.028^9 = 0.04
I got 0.04 L/day but my textbook answer says 0.003963 L/day. I really don't understand why.
2 answers
You forgot to multiply by 0.099
ok thanks