Sau has 30 pens and Randy has 14. How many pens must Randy give Sau so that Sau shall have 3 times as many as Randy

Answer 1

Let x be the number of pens Randy must give Sau.

After Randy gives x pens to Sau, Sau will have 30 + x pens and Randy will have 14 - x pens.

The problem states that Sau must have 3 times as many pens as Randy. Therefore, we can write the equation:

30 + x = 3(14 - x)

Expanding the right side:

30 + x = 42 - 3x

Moving variables to one side:

4x = 12

Dividing by 4:

x = 3

Therefore, Randy must give Sau 3 pens.