Fx = 100*Cos37 = 79.86 N.
Wb = m*g = 10kg * 9.8N/kg = 98 N. =
Weight of buggy.
a=(Fx-Fk)/m = (79.86-60)/10=1.99 m/s^2
Sarah is pushing a 10 kg buggy and exerts a force of 100 N along the handle. If the handle is elevated at 37° to the horizontal, determine the component of the force that will move the buggy forward. If a frictional force of 60 N exists as she pushes it over a grass covered parkway, determine the acceleration of the buggy.
1 answer
1 answer