When a horse pulls a 54 kg buggy down the road with a force of 56 N, the buggy hitch makes an angle of 25 degrees above the horizontal. If the force of friction on the buggy is 3 N, what is the buggy's acceleration? Report your answer to 2 decimal places. Do not include the units in your answer or the computer will mark the problem wrong.

asked by Anna

4 years ago

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1 answer

the net force is 56cos25°-3 = 47.75N
F = ma, so a = 47.75N/54kg = 0.884 m/s^2

answered by oobleck

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Question

When a horse pulls a 54 kg buggy down the road with a force of 56 N, the buggy hitch makes an angle of 25 degrees above the horizontal. If the force of friction on the buggy is 3 N, what is the buggy's acceleration? Report your answer to 2 decimal places. Do not include the units in your answer or the computer will mark the problem wrong.

1 answer

the net force is 56cos25°-3 = 47.75N
F = ma, so a = 47.75N/54kg = 0.884 m/s^2

oobleck · Answer

the net force is 56cos25°-3 = 47.75N F = ma, so a = 47.75N/54kg = 0.884 m/s^2