I will try crate 1
m = 30 kg
F = 100 N
1. impulse = F t = 100 * 3 = 300 Ns yes
2. Force = change in momentum/time
and initial momentum = 0
so
100 = change in momentum/3
so
change in momentum = 300 kg m/s = Ns
(by the way if there is a difference between change of momentum and impluse I do not know it.)
3. m v = momentum = 300
so v = 300/30 = 10 m/s
4. same as answers 1. and 2. since initial momentum is zero (at rest)
Sam pushes crates starting form rest across the floor of his classroom for 3 s with a net force as shown above. For each crate, rank the following from greatest to least: A 100N/30kg, B 75N/20kg C 50N/10kg
1. Impulse delivered
2. Change in momentum
3. Final speed
4. Momentum in 3s
This is what I have so far:
1. Formula I=Ft: A) I=100N(3s) 300Ns B) I=75N(3s)=225Ns C) I=50N(3s)=150Ns
2. Formula F=ma: A) F=100N(30kg)=3000Nkg B) F=75N(20kg)= 1500Nkg C) F=50N(10kg)=500Nkg
I cannot figure out how to find 3 and 4. If you could please write the formula for the answer
2 answers
Forget the formulas, think !!!!
2 answers