mols Fe2O3 in 24.6 g Fe2O3 = grams Fe2O3/molar mass Fe2O3 = 24.6/approx 160 = approx 0.15.
Then mols Fe = 0.15 mols Fe2O3 x (2 mols Fe/1 mol Fe2O3) = 0.15 x 2/1 = ?
You need to run through it with better accuracy than my estimates.
Rust formula is rep by Fe2O3
How many moles of Fe are present in 24.6 g of the compound
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