Rewrite the irrational square root V 48 as the product of an integer and another irrational square root. (1 point)

Question

• 4V12
2V 24
• 2V12
04V3

Answer 1

To rewrite \( \sqrt{48} \) as the product of an integer and another irrational square root, we can simplify it as follows:

1. First, factor \( 48 \) into \( 16 \times 3 \), since \( 16 \) is a perfect square.
2. Then, we take the square root: \[ \sqrt{48} = \sqrt{16 \times 3} = \sqrt{16} \times \sqrt{3} = 4\sqrt{3}. \]

So, the correct answer is \( 4\sqrt{3} \).