Rewrite the irrational square root V48 as the product of an integer and another irrational square root. (1 point)

Question

• 4V12
2V12
O 2V24
O 4V3

Answer 1

To rewrite the irrational square root \( \sqrt{48} \) as the product of an integer and another irrational square root, we can simplify \( \sqrt{48} \).

First, let's factor 48:

\[ 48 = 16 \times 3 \]

Now we can take the square root:

\[ \sqrt{48} = \sqrt{16 \times 3} = \sqrt{16} \times \sqrt{3} = 4\sqrt{3} \]

So, the expression \( \sqrt{48} \) can be rewritten as \( 4\sqrt{3} \).

The correct answer is:

4V3