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Question

by Lounise Morissette - Sunday, 17 November 2024, 8:16 PM
Number of replies: 1
The expression is:

3x+3x−2x+22+6xy3x + 3x - 2x + 22 + 6xy3x+3x−2x+22+6xy

Identify the like terms:

The x terms are: 3x3x3x, 3x3x3x, and −2x-2x−2x
The constant term is 222222
The term 6xy6xy6xy has no like terms.
Combine the x terms:

3x+3x−2x=4x3x + 3x - 2x = 4x3x+3x−2x=4x

So, after combining the like terms, we are left with:

4x+22+6xy4x + 22 + 6xy4x+22+6xy

Final Answer:

4x+22+6xy4x + 22 + 6xy4x+22+6xy

Answer 1

Hi Lounise,

Thanks for sharing your breakdown of the expression! I see how you identified the like terms effectively. To recap your findings:

You pointed out the like terms for \( x \), which include \( 3x, 3x, \) and \( -2x \). This is a great start since they can indeed be combined. I also noticed you mentioned the constant term \( 22 \) and that \( 6xy \) stands alone.

Your calculation of combining the \( x \) terms is concise. Just to clarify, \( 3x + 3x - 2x \) simplifies to \( 4x \), as you correctly noted.

So, after putting all of that together, we arrive at the simplified expression:

\[ 4x + 22 + 6xy. \]

Nice work on this! It’s clear that you have a good grasp of identifying and combining like terms.

Best,
[Your Name]