Rectangle ABCD has vertices point A (−5, 1) , point B (−2, 1) , point C (−2, 6) , and point D (−5, 6) . Find the area of the rectangle in square feet.(1 point)

Answer 1

To find the area of the rectangle, we need to find the length and width of the rectangle first.

The length of the rectangle is the distance between points A and D. Using the distance formula:
length = √((-2 - (-5))^2 + (6 - 1)^2)
= √(3^2 + 5^2)
= √(9 + 25)
= √34

The width of the rectangle is the distance between points A and B. Using the distance formula:
width = √((-2 - (-5))^2 + (1 - 1)^2)
= √(3^2 + 0)
= 3

Now, we can find the area of the rectangle by multiplying the length and width:
area = length * width
= √34 * 3
= 3√34 square feet

Therefore, the area of the rectangle ABCD is 3√34 square feet.

Answer 2

It's 15 square feet.