int a = 10;
int b = 5;
int total = 0;
printf("%d + %d = %d\n", a, b, total);
printf("%d - %d = %d\n", a, b, total);
printf("%d * %d = %d\n", a, b, total);
printf("%d / %d = %d\n", a, b, total);
/*Without an array*/
if(var == 1)
{
return 1;
}
else if(var == 2)
{
return 1;
}
else if(var == 3)
{
return 1;
}
else if(var == 4)
{
return 1;
}
else if(var == 5)
{
return 1;
}
else
{
return 0;
}
I think that is what you want, This is just simple C code. Nothing special.
Read two numbers from the keyboard Display the menu options as follows: 1 - computes the sum of two numbers. 2 - computes the difference (first minus second). 3 - computes the product of the two numbers. 4 - if the second number is not zero, computes the quotient (first divided by second). 5 - terminates the program If the code is not equal to 1,2,3,4 or 5 - displays an error message. The program is then to display the two numbers, the integer code and the computed result to the screen. Use CASE structure in this algorithm.
1 answer
1 answer