To determine how many biking outfits Rashon can purchase while staying within his budget, we need to calculate how much money he has left after his purchases.
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Calculate the total spending on items already purchased:
- Cost of the bicycle: $481.28
- Cost of 3 reflectors: \(3 \times 10.78 = 32.34\)
- Cost of bike gloves: $32.64
Now, we add these amounts together:
\[ \text{Total spending} = 481.28 + 32.34 + 32.64 \]
Calculating this:
\[ 481.28 + 32.34 = 513.62 \] \[ 513.62 + 32.64 = 546.26 \]
Therefore, Rashon has spent a total of $546.26.
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Calculate how much money is left:
- Rashon started with $780, so the amount of money he has left is:
\[ 780 - 546.26 = 233.74 \]
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Define the inequality for the number of outfits ($o$) he can purchase:
- Each biking outfit costs $44.95. The total cost for $o$ outfits will be \(44.95o\).
- The amount of money Rashon has left must be greater than or equal to the cost of the outfits:
\[ 44.95o \leq 233.74 \]
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Solving the inequality:
Divide both sides by 44.95:
\[ o \leq \frac{233.74}{44.95} \]
Now calculate the right-hand side:
\[ \frac{233.74}{44.95} \approx 5.20 \]
Since $o$ must be a whole number (he can only buy complete outfits), we round down to 5.
Thus, the final inequality is:
\[ o \leq 5 \]
This means Rashon can purchase at most 5 outfits with the remaining money he has.