To determine how many biking outfits Rashawn can buy while staying within his budget after making his purchases, we need to start by calculating how much money he has left after his initial purchases.
- Initial Budget: $780
- Cost of Bicycle: $481.28
- Cost of Bicycle Reflectors: \(3 \text{ reflectors} \times 10.78 \text{ each} = 32.34\)
- Cost of Biking Gloves: \(32 + 0.64 = 32.64\)
Now we can sum up the costs of the items he has bought:
\[ \text{Total spent} = \text{Cost of Bicycle} + \text{Cost of Reflectors} + \text{Cost of Gloves} \]
\[ \text{Total spent} = 481.28 + 32.34 + 32.64 = 546.26 \]
Next, we calculate how much money Rashawn has left:
\[ \text{Money left} = \text{Initial Budget} - \text{Total spent} \]
\[ \text{Money left} = 780 - 546.26 = 233.74 \]
Now, let \( x \) be the number of biking outfits he wants to buy. Each biking outfit costs $44.95, so the total cost for \( x \) outfits would be \( 44.95x \). To stay within his remaining budget, we can set up the inequality:
\[ 44.95x \leq 233.74 \]
To solve for \( x \):
\[ x \leq \frac{233.74}{44.95} \]
Calculating:
\[ x \leq 5.20 \]
Since Rashawn cannot buy a fraction of an outfit, we round down to the nearest whole number. Therefore, Rashawn can buy a maximum of 5 biking outfits while staying within his budget.
Summary
The inequality to determine the number of outfits Rashawn can buy is:
\[ 44.95x \leq 233.74 \]
And he can buy up to 5 outfits.