Questions:
1. If an object is projected horizontally from a height of 5 m with an initial velocity of 7 m/s, what is the value of x0x0?
2. If you are given values for Δx, v⃗ , and ΔtΔx, v→, and Δt, which kinematic equation could be used to find v⃗ 0v→0?
3. For horizontally-launched projectiles, which of the following describes acceleration in both directions with a⃗ x=0a→x=0 and a⃗ y=−9.8 m/s2a→y=−9.8 m/s2.
4. Your friend says you can’t use the equation Δx=v⃗ 0Δt + 12a⃗ (Δt)2Δx=v→0Δt + 12a→(Δt)2 to find the horizontal displacement of a horizontal projectile with a constant velocity because you don’t know the acceleration in the horizontal direction. Is your friend correct? Why or why not?
Answers:
1.×0=0
2.Δx =(v⃗ +v⃗ 02)Δt
3. Acceleration is constant in both directions.
4. My friend is incorrect. If the velocity is constant, then the horizontal acceleration is zero.
(You can trust my answers if YOU want too)
— Coconut🥥
0 answers