To find the final position of the object after 1 second, we can plug the given values into the equation for motion:
x = x0 + v0t + 1/2at^2
Given:
x0 = 2 m (starting position)
v0 = 15 m/s (starting velocity)
t = 1 s (time)
Plugging in the values, we get:
x = 2 + 15(1) + 1/2(0)(1)^2
Simplifying:
x = 2 + 15 + 0
x = 17
Therefore, the final position of the object after 1 second is 17 meters.
Question
Use the equation for motion to answer the question.
x=x0+v0t+12at2
An object has a starting position of 2 m, a starting velocity of 15 m/s, and is moving at a constant speed. Which option shows the final position of the object after 1 s?
1 answer
1 answer