Asked by Becky
Question
Find an equation of the set of all points equidistant from the points
A(−2, 5, 2) and B(5, 1, −3).
Answers
Answered by
MathMate
Think of two points in space.
The set of all points equidistant from the points is therefore a plane that separates the two points, right in the middle.
Also the line joining the two points would be perpendicular to the plane.
The mid-point between the two points would evidently lie on the plane.
(1) Find the mid-point between the two given points using the mid-point formula. Let this be p0.
(2) Find the vector AB joining the two given points. Then AB is the normal vector to the plane we're looking for.
Let AB=<a,b,c>
(3) Use the components of the normal vector AB (a,b,c) to form the equation of the required plane:
a(x-x0)+b(y-y0)+c(z-z0)=0
where (x0,y0,z0) is the mid-point P0 between A and B.
If you need more details, please post.
The set of all points equidistant from the points is therefore a plane that separates the two points, right in the middle.
Also the line joining the two points would be perpendicular to the plane.
The mid-point between the two points would evidently lie on the plane.
(1) Find the mid-point between the two given points using the mid-point formula. Let this be p0.
(2) Find the vector AB joining the two given points. Then AB is the normal vector to the plane we're looking for.
Let AB=<a,b,c>
(3) Use the components of the normal vector AB (a,b,c) to form the equation of the required plane:
a(x-x0)+b(y-y0)+c(z-z0)=0
where (x0,y0,z0) is the mid-point P0 between A and B.
If you need more details, please post.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.