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A swimming pool, 20.0 m ✕ 12.5 m, is filled with water to a depth of 3.85 m. If the initial temperature of the water is 18.9°C, how much heat must be added to the water to raise its temperature to 28.7°C? Assume that the density of water is 1.000 g/mL.
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DrBob222
Convert 20m, 12.5m and 3.85m to cm, then pool L x W x depth = volume in cc
mass H2O is volume in cc x 1.00 g/cc.
Then q = mass H2O x specific heat H2O x (Tfinal-Tinitial). Substitute and solve for q.
mass H2O is volume in cc x 1.00 g/cc.
Then q = mass H2O x specific heat H2O x (Tfinal-Tinitial). Substitute and solve for q.
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