Asked by danny
The average swimming pool has a volume of about 28,000 gallons. Suppose a swimming pool was filled with pH 7.00 water. However, you need to adjust the pH to 4.75. How much acid pool acid (which is 1.00 M HCl) do you need to add to the pool? The units are liters.
convert 28000divided 3.785=105980
(10-7)(105980)=?
(10-4.75)=?
convert 28000divided 3.785=105980
(10-7)(105980)=?
(10-4.75)=?
Answers
Answered by
DrBob222
I think you converted the wrong way.
28,000 gallons x (3.785 L/gallon) = 1E5 ESTIMATED. You need a better answer than that.
How many mols do you need? That's M x L = approx 1E5 mol HCl.
M HCl = mols HCl/L HCl. You know M and mols, solve for L. That really looks like a simple problem to me. Think in mols. That's the secret to most chemistry problems.
28,000 gallons x (3.785 L/gallon) = 1E5 ESTIMATED. You need a better answer than that.
How many mols do you need? That's M x L = approx 1E5 mol HCl.
M HCl = mols HCl/L HCl. You know M and mols, solve for L. That really looks like a simple problem to me. Think in mols. That's the secret to most chemistry problems.
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