Probability of making one shot = 55% = 0.55
Probability of missing one shot = 1 - 0.55 = 0.45
Probability of making all three shots = 0.55 * 0.55 * 0.55 = 0.166375
Therefore, the percent chance that John makes all three free throws is 16.6375%.
Question
John has to make all 3 free throws to win the game. Assume each free throw is an independent event and that the pressure of the situation has no impact on him. If John is a 55% free throw shooter what is the percent chance that John makes all three free throws? Do not round your answer. (Click Here for Help Video)(10 points)
John's probability to make all three shots is:
%
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