From the given information, we know that the probability of John making a free throw is 0.55 and the probability of him missing a free throw is 0.45.
To find the probability of John making all three free throws, we multiply the probability of him making a free throw by itself three times:
0.55 * 0.55 * 0.55 = 0.166375
Therefore, the probability that John makes all three free throws is 0.166375 or 16.6375%.
John has to make all 3 free throws to win the game. Assume each free throw is an independent event and that the pressure of the situation has no impact on him. If John is a 55% free throw shooter what is the percent chance that John makes all three free throws? Do not round your answer
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