Asked by Emerson
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Part 1
Find the distance between the pair of points.
Upper E left parenthesis 10 comma negative 2 right parenthesisE(10,−2), Upper F left parenthesis negative 2 comma 3 right parenthesisF(−2,3)
Question content area bottom
Part 1
ddequals=enter your response here
Part 1
Find the distance between the pair of points.
Upper E left parenthesis 10 comma negative 2 right parenthesisE(10,−2), Upper F left parenthesis negative 2 comma 3 right parenthesisF(−2,3)
Question content area bottom
Part 1
ddequals=enter your response here
Answers
There are no human answers yet.
Answered by
GPT-4o mini
To find the distance between two points \( E(10, -2) \) and \( F(-2, 3) \) in a 2-dimensional plane, we use the distance formula given by:
\[
d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}
\]
Here, \( (x_1, y_1) \) is the coordinates of point E and \( (x_2, y_2) \) is the coordinates of point F:
- \( E(10, -2) \): \( x_1 = 10 \) and \( y_1 = -2 \)
- \( F(-2, 3) \): \( x_2 = -2 \) and \( y_2 = 3 \)
Now, we can plug the values into the distance formula:
\[
d = \sqrt{((-2) - 10)^2 + (3 - (-2))^2}
\]
Calculating the differences:
\[
d = \sqrt{(-12)^2 + (5)^2}
\]
Calculating the squares:
\[
d = \sqrt{144 + 25}
\]
Now, add the results:
\[
d = \sqrt{169}
\]
Taking the square root:
\[
d = 13
\]
Thus, the distance between the points \( E \) and \( F \) is:
\[
\boxed{13}
\]
\[
d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}
\]
Here, \( (x_1, y_1) \) is the coordinates of point E and \( (x_2, y_2) \) is the coordinates of point F:
- \( E(10, -2) \): \( x_1 = 10 \) and \( y_1 = -2 \)
- \( F(-2, 3) \): \( x_2 = -2 \) and \( y_2 = 3 \)
Now, we can plug the values into the distance formula:
\[
d = \sqrt{((-2) - 10)^2 + (3 - (-2))^2}
\]
Calculating the differences:
\[
d = \sqrt{(-12)^2 + (5)^2}
\]
Calculating the squares:
\[
d = \sqrt{144 + 25}
\]
Now, add the results:
\[
d = \sqrt{169}
\]
Taking the square root:
\[
d = 13
\]
Thus, the distance between the points \( E \) and \( F \) is:
\[
\boxed{13}
\]
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