Question

Charles wants to go on a fishing trip. The price of the excursion varies based on the length of the trip. The line of best fit for these data is y=50x+75
, where the price of the trip is based on the number of hours of the trip. What prediction can be made about the length of his trip based on the line of best fit?

(1 point)
Responses

Charles can take a 6-hour trip for less than $400.
Charles can take a 6-hour trip for less than $400.

For $200, Charles can travel for 2 hours.
For $200, Charles can travel for 2 hours.

Charles can go on a 1-hour trip for less than $100.
Charles can go on a 1-hour trip for less than $100.

Charles pays $300 for a 3-hour trip.

1 answer

To analyze the line of best fit given by the equation \( y = 50x + 75 \), we can substitute specific values of \( x \) (the number of hours of the trip) to find the corresponding price \( y \).

  1. For a 6-hour trip (\( x = 6 \)): \[ y = 50(6) + 75 = 300 + 75 = 375 \] This prediction means that Charles can take a 6-hour trip for $375.

  2. For a 2-hour trip (\( x = 2 \)): \[ y = 50(2) + 75 = 100 + 75 = 175 \] This prediction means that for $200, Charles can actually only travel for 2 hours at a price of $175.

  3. For a 1-hour trip (\( x = 1 \)): \[ y = 50(1) + 75 = 50 + 75 = 125 \] This prediction means that Charles can go on a 1-hour trip for $125 which is not less than $100.

  4. For a 3-hour trip (\( x = 3 \)): \[ y = 50(3) + 75 = 150 + 75 = 225 \] This prediction means that Charles pays $225 for a 3-hour trip, not $300.

Now let's analyze each response:

  • Charles can take a 6-hour trip for less than $400. (True: $375 is less than $400)
  • For $200, Charles can travel for 2 hours. (False: It’s actually $175 for 2 hours)
  • Charles can go on a 1-hour trip for less than $100. (False: It’s actually $125 for 1 hour)
  • Charles pays $300 for a 3-hour trip. (False: He actually pays $225)

Thus, the correct statement based on the line of best fit is:

Charles can take a 6-hour trip for less than $400.