Charles wants to go on a fishing trip. The price of the excursion varies based on the length of the trip. The line of best fit for these data is y=50x+75

Question

, where the price of the trip is based on the number of hours of the trip. What prediction can be made about the length of his trip based on the line of best fit?

(1 point)
Responses

Charles can take a 6-hour trip for less than $400.
Charles can take a 6-hour trip for less than $400.

For $200, Charles can travel for 2 hours.
For $200, Charles can travel for 2 hours.

Charles can go on a 1-hour trip for less than $100.
Charles can go on a 1-hour trip for less than $100.

Charles pays $300 for a 3-hour trip.

Answer 1

To predict the cost of a fishing trip with the given line of best fit \( y = 50x + 75 \), where \( y \) is the price in dollars and \( x \) is the number of hours, we can evaluate each response option by plugging in the values for \( x \).

1. Charles can take a 6-hour trip for less than $400.

   • Plugging in \( x = 6 \): \[ y = 50(6) + 75 = 300 + 75 = 375 \]
   • This statement is true since 375 is less than 400.

2. For $200, Charles can travel for 2 hours.

   • Plugging in \( x = 2 \): \[ y = 50(2) + 75 = 100 + 75 = 175 \]
   • This statement is false because the price for 2 hours is $175, not $200.

3. Charles can go on a 1-hour trip for less than $100.

   • Plugging in \( x = 1 \): \[ y = 50(1) + 75 = 50 + 75 = 125 \]
   • This statement is false because the price for a 1-hour trip is $125, which is not less than $100.

4. Charles pays $300 for a 3-hour trip.

   • Plugging in \( x = 3 \): \[ y = 50(3) + 75 = 150 + 75 = 225 \]
   • This statement is false because the price for a 3-hour trip is $225, not $300.

Based on the evaluations, the only correct prediction is: Charles can take a 6-hour trip for less than $400.