To solve the expression \( 3^7 \cdot 3^{-9} \) using the properties of integer exponents, we will first combine the exponents.
The property of exponents that applies here is: \[ a^m \cdot a^n = a^{m+n} \]
So, we can combine the exponents: \[ 3^7 \cdot 3^{-9} = 3^{7 + (-9)} = 3^{-2} \]
Next, we convert \( 3^{-2} \) to a positive exponent. Using the property: \[ a^{-n} = \frac{1}{a^n} \]
We can rewrite \( 3^{-2} \) as: \[ 3^{-2} = \frac{1}{3^2} \]
Now we calculate \( 3^2 \): \[ 3^2 = 9 \]
Therefore: \[ 3^{-2} = \frac{1}{9} \]
So the equivalent expression with only positive exponents is \( \frac{1}{9} \).
In conclusion, the final answer is: \[ \frac{1}{9} \]