Question

Apply the Properties of Integer Exponents to generate equivalent expressions to (43 ⋅ 7−2)−579 ⋅ 4−13
with only positive exponents, then solve the expression. Your answer will be a simplified fraction with no remaining exponents.(1 point)

1 answer

To simplify the expression \( (43 \cdot 7^{-2})^{-579} \cdot 4^{-13} \) using the properties of integer exponents and generate an equivalent expression with only positive exponents, we can follow these steps:

  1. Use the property \( (a^m)^n = a^{m \cdot n} \) to handle the exponent on the first term.

    \[ (43 \cdot 7^{-2})^{-579} = 43^{-579} \cdot (7^{-2})^{-579} \]

    Simplifying \( (7^{-2})^{-579} \):

    \[ (7^{-2})^{-579} = 7^{2 \cdot 579} = 7^{1158} \]

    Now, we have:

    \[ (43 \cdot 7^{-2})^{-579} = 43^{-579} \cdot 7^{1158} \]

  2. Next, we combine it with \( 4^{-13} \):

    \[ 43^{-579} \cdot 7^{1158} \cdot 4^{-13} \]

    We can also convert \( 4^{-13} \) using the property:

    \[ 4^{-13} = \frac{1}{4^{13}} \]

    This allows us to rewrite the entire expression as:

    \[ \frac{7^{1158}}{43^{579} \cdot 4^{13}} \]

  3. Now we convert \( 4^{13} \) into base powers of \( 2 \):

    \[ 4^{13} = (2^2)^{13} = 2^{26} \]

    Substituting this back into the expression gives:

    \[ \frac{7^{1158}}{43^{579} \cdot 2^{26}} \]

Now we have our final expression with only positive exponents:

\[ \frac{7^{1158}}{43^{579} \cdot 2^{26}} \]

The expression is now simplified and does not contain any negative exponents. Since the problem asks for a simplified fraction and doesn't specify numerical evaluation beyond this structure, this is our final answer:

\[ \frac{7^{1158}}{43^{579} \cdot 2^{26}} \]

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