To find the number of students in Ms. Jay's homeroom who would be expected to have an A, we can use proportions.
The proportion of students with an A in Ms. Darnell's class is 9/72. We can set up a proportion to find the expected number of students in Ms. Jay's homeroom (let's call it x) who would have an A:
9/72 = x/16
To solve for x, we can cross multiply:
72x = 9 * 16
72x = 144
Dividing both sides by 72:
x = 144/72
x = 2
Therefore, based on the given rate, we would expect 2 out of the 16 students in Ms. Jay's homeroom to have an A.
Question 8%0d%0aA)Of the 72 students who have Ms. Darnell for Health/PE, 9 have an A. At this rate, how many of the 16 students in Ms. Jay’s homeroom would you expect to have an A?
1 answer