At the same rate, we can expect 9 out of 72 students to have an A in Ms. Darnell's class.
To find out how many students in Ms. Jay's homeroom would be expected to have an A, we can use proportions.
The proportion of students who have an A in Ms. Darnell's class is 9/72.
We can set up a proportion using this information:
9/72 = x/16
To find x, we need to cross-multiply and solve for x:
72x = 9 * 16
72x = 144
x = 144/72
x = 2
Therefore, we would expect 2 out of the 16 students in Ms. Jay's homeroom to have an A.
Of the 72 students who have Ms. Darnell for Health/PE, 9 have an A. At this rate, how many of the 16 students in Ms. Jay’s homeroom would you expect to have an A? (1 point)
students
1 answer
1 answer