In the nuclear reaction you provided:
\[ ^{35}{16}S \rightarrow __ + ^{35}{17}A \]
The reaction indicates that sulfur-35 (\(^{35}_{16}S\)) emits a particle and becomes a different isotope or element (denoted as \(A\) with an atomic number of 17). The original sulfur has an atomic number of 16 and when it emits a particle resulting in an atomic number of 17, it suggests that it is gaining a proton, which is characteristic of beta decay.
In beta decay, a neutron in the nucleus decays into a proton and an electron (the beta particle) is emitted. This would increase the atomic number by one (from 16 to 17), which matches the scenario presented.
Thus, the correct type of nuclear radiation given off in this reaction is:
a. Beta radiation.
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