To identify the type of nuclear radiation in the given nuclear reaction:
\[ ^{35}{16}S \rightarrow , ? , + , ^{35}{17}Cl \]
We notice that sulfur (\(^{35}{16}S\)) is transforming into chlorine (\(^{35}{17}Cl\)).
- The atomic mass (nucleon number) remains the same at 35.
- The atomic number increases from 16 (for sulfur) to 17 (for chlorine).
This means that a neutron is being converted into a proton, which is a characteristic of beta radiation. In beta decay (\(\beta^-\)), a neutron decays into a proton, emitting a beta particle (which is an electron).
Thus, the answer is:
c. Beta radiation