Asked by Ashley
Question :
4 moles of A(g) is added to a fixed volume container and left until they arrive at the equilibrium status.
2A(g) <===> A2(g)
At 127 C total pressure of the equilibrium system is 8.314*10^5 Pa and the density of the mixture of gas is 10 kg/m^3 . If the relative atomic weight of A is 30 find the partial pressure of A2(g).
My first attempt towards solving this question is applying PM=dRT equation, where I took d as (30+x) (x is the relative atomic mass of A2(g) )
Then I got x=220
My next thought is finding moles of A2(g) and then obtaining the partial pressure of it.Then again I'm getting another unknown value for moles of A2(g) as follows;
2A(g) <===> A2(g)
initial(moles) 4 -
final (moles) (4-2y) y
How do I solve this?
4 moles of A(g) is added to a fixed volume container and left until they arrive at the equilibrium status.
2A(g) <===> A2(g)
At 127 C total pressure of the equilibrium system is 8.314*10^5 Pa and the density of the mixture of gas is 10 kg/m^3 . If the relative atomic weight of A is 30 find the partial pressure of A2(g).
My first attempt towards solving this question is applying PM=dRT equation, where I took d as (30+x) (x is the relative atomic mass of A2(g) )
Then I got x=220
My next thought is finding moles of A2(g) and then obtaining the partial pressure of it.Then again I'm getting another unknown value for moles of A2(g) as follows;
2A(g) <===> A2(g)
initial(moles) 4 -
final (moles) (4-2y) y
How do I solve this?
Answers
There are no human answers yet.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.