Question 4 (10 points)

Question

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Use the information and data table to answer the written response AND multiple choice question.

Students had two batteries and two different resistors. During four trials, they build four different circuits and plan to measure the circuit’s current in Amps according to following table.

Written Response: 8 pts

Give the current for each trial.

Multiple Choice: 2pts

Which trial would the students measure the smallest current in the circuit?

Trial 1

Trail 2

Trial 3

Trial 4

chart
Trial number:1,2,3,4
voltage(V):1.5,1.5,3.0,3.0
Resistance:200,100,200,100
current: nothing down

Answer 1

To calculate the current for each trial, we can use Ohm's Law, which states that:

\[ \text{Current (I)} = \frac{\text{Voltage (V)}}{\text{Resistance (R)}} \]

Now, we will calculate the current for each trial based on the provided values.

Trial 1:

• Voltage (V): 1.5 V
• Resistance (R): 200 Ω

\[ I = \frac{1.5 V}{200 Ω} = 0.0075 A , \text{or} , 7.5 mA \]

Trial 2:

• Voltage (V): 1.5 V
• Resistance (R): 100 Ω

\[ I = \frac{1.5 V}{100 Ω} = 0.015 A , \text{or} , 15 mA \]

Trial 3:

• Voltage (V): 3.0 V
• Resistance (R): 200 Ω

\[ I = \frac{3.0 V}{200 Ω} = 0.015 A , \text{or} , 15 mA \]

Trial 4:

• Voltage (V): 3.0 V
• Resistance (R): 100 Ω

\[ I = \frac{3.0 V}{100 Ω} = 0.030 A , \text{or} , 30 mA \]

Now summarizing the currents for each trial:

• Trial 1: 0.0075 A or 7.5 mA
• Trial 2: 0.015 A or 15 mA
• Trial 3: 0.015 A or 15 mA
• Trial 4: 0.030 A or 30 mA

Written Response:

• Trial 1: Current = 0.0075 A (7.5 mA)
• Trial 2: Current = 0.015 A (15 mA)
• Trial 3: Current = 0.015 A (15 mA)
• Trial 4: Current = 0.030 A (30 mA)

Multiple Choice:

Which trial would the students measure the smallest current in the circuit?

• Answer: Trial 1 (0.0075 A or 7.5 mA)