call F = force exerted on car by tires through engine power
total horizontal force on car = force exerted by tires - resistive force
= F - 160
so
F - 160 = m a
F = 160 + 1200*0.2 = 160 +240 = 400 N
power = 400 * speed = 400 * 10 = 4000 Joules/second or Watts
Question 11 Unsaved
A car of mass 1200 kg travels along a horizontal road at a speed of 10 m s-1. At the time
it begins to accelerate at 0.2 m s-2, the total resistive force acting on the car is 160 N. What is
the total output power developed by the car as it begins the acceleration?
1 answer
2 answers