Let's answer each of the questions one by one:
Question 1
Stephen is incorrect because he added instead of subtracted. To find the slope using the formula \( \Delta y / \Delta x = (y_2 - y_1) / (x_2 - x_1) \), Stephen should be using:
- \( y_2 = 8 \) and \( y_1 = -6 \)
- \( x_2 = 0 \) and \( x_1 = 8 \)
The correct calculation should be: \[ \text{slope} = \frac{8 - (-6)}{0 - 8} = \frac{8 + 6}{0 - 8} = \frac{14}{-8} = -\frac{7}{4} \]
Question 2
Statement #1 is the best way for Krystina to determine if the lines are parallel. Two lines are parallel if they have the same slope and different y-intercepts.
Question 3
Line A is perpendicular to Line C. Line A has a slope of -1/2, while Line C has a slope of 1/2. Slopes that multiply to -1 are perpendicular.
Question 4
To solve for x
, we know that \( \angle UWS \) and \( \angle QVU \) are alternate interior angles formed by parallel lines \( PQ \parallel RS \):
Given: \( \angle UWS = 4x - 18 \) and \( \angle QVU = 102^\circ \).
So, we set them equal: \[ 4x - 18 = 102 \] Adding 18 to both sides gives: \[ 4x = 120 \] \[ x = 30 \] Thus, \( x = 30 \).
Question 5
Transitive Property of Equality. The transitive property allows you to substitute equal angles in place of one another.
Question 6
Correct statements:
- \( \angle FDP \cong \angle EPG \) (because they are corresponding angles since ED is a perpendicular bisector of GF)
- \( DP \cong EP \) (because ED is a perpendicular bisector).
Question 7
To find the measure of one interior angle of a regular hexagon, use the formula: \[ \text{Interior angle} = \frac{(n-2) \times 180}{n} \] Where \( n = 6 \) for a hexagon: \[ \frac{(6 - 2) \times 180}{6} = \frac{720}{6} = 120° \] So the measure of one interior angle is 120°.
Question 8
Given \( BD = x + 20 \) and \( AC = 4x + 14 \) in a rectangle \( ABCD \), we know \( AC = BD \). Thus: \[ 4x + 14 = x + 20 \] Solving for \( x \): \[ 4x - x = 20 - 14 \implies 3x = 6 \implies x = 2 \] Now substitute \( x \) back into \( AC \): \[ AC = 4(2) + 14 = 8 + 14 = 22 \] So, AC = 22.
Question 9
Given angles measure \( (3x-7) \) and \( (x+15) \): Assuming they are supplementary: \[ (3x - 7) + (x + 15) = 180 \] Simplifying this: \[ 4x + 8 = 180 \implies 4x = 172 \implies x = 43 \] Thus \( \angle D = x + 15 = 43 + 15 = 58 \).
Question 10
To find when Ema's quadrilateral ABCD is a parallelogram, we equate opposite sides:
- \( 40y = 8y + 32 \) leads to \( 32y = 32 \implies y = 16 \).
- \( 4 + 3x = 9x - 20 \) leads to \( 3x - 9x = -20 - 4 \implies -6x = -24 \implies x = 4 \).
So the values are x = 4 and y = 16.
Question 11
SE is congruent to VE. In any parallelogram, opposite sides or segments are congruent.
Question 12
The centroids of triangles are calculated using the averages of the vertices. Assuming the triangles vertices are provided and averaging \( (x_1, y_1), (x_2, y_2), (x_3, y_3) \): This requires coordinates for the precise answer.
Question 13
Given \( BE = 2x+9 \) and \( EC = 12x-11 \) with \( BE = EC \): \[ 2x + 9 = 12x - 11 \] \[ 9 + 11 = 12x - 2x \implies 20 = 10x \implies x = 2 \]
Question 14
Using \( \angle DAB = 124° \):
- \( m∠ABC = \text{same as } DAB = 124° \)
- \( m∠AEB = 180° - 124° = 56° \)
- \( m∠ADE = 124° \), angles opposite in rhombus are equal.
Question 15
Could you provide more context or details for this question?
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