To determine if quadrilateral QRST is a parallelogram, we can use the property that the sum of the interior angles of a quadrilateral is 360°. Given that angle Q measures 108° and angle R measures \(108 - 2x\), we can denote the measures of angles S and T as \(s\) and \(t\), respectively. Thus, we have the equation:
\[ 108 + (108 - 2x) + s + t = 360 \]
Simplifying this gives:
\[ 216 - 2x + s + t = 360 \quad \Rightarrow \quad s + t = 144 + 2x \]
For QRST to be a parallelogram, opposite angles must be equal. Therefore, angle S must equal angle R, and angle T must equal angle Q, leading us to the equations:
\[ s = 108 - 2x \quad \text{and} \quad t = 108 \]
Substituting \(t = 108\) into the previous equation, we get:
\[ s + 108 = 144 + 2x \quad \Rightarrow \quad s = 144 + 2x - 108 \quad \Rightarrow \quad s = 36 + 2x \]
Setting the equations for \(s\) equal, we have:
\[ 36 + 2x = 108 - 2x \] \[ 4x = 72 \quad \Rightarrow \quad x = 18 \]
Thus, QRST is a parallelogram, and \(x\) solves to 18.