Question

The vertices of quadrilateral ABCD are A(0, 5), B(9, 2), C (7, –4), and D(–2, –1). Is ABCD a rectangle? Explain.
AB = √(9^2+3^2) = √90
Check the other lengths. If you find that AB=CD and BC=AD, then you have a parallelogram.
AB has slope -1/3
BC has slope 3 so AB⊥BC
Make sure that AD⊥CD

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