This is the same style of question I just answered for you in the previous post.
Just follow the same steps.
Q2. An agriculture field is rectangular,with dimensions 100m by 42m.A 20m deep well of diameter 14m is dug in acorner of the field and the earth taken out is spread evenly over the remaining part of the field. Find the increase in the level of the field.
11 answers
72cm
h:1.465m
0.8m
76cm
DESSIE
Chgg
DESSIE
I need to check, please
So, d/t......
Volume Of well=22/7×7×7×20
=3,080m^3
Area Of filed =100×42= 4200m^2
The area of the remaning part of the filed=the area of field - the area of well, so. 4200m^2 - 154m^2 (22/7×7×7)=4046m^2
The volume of the riseing filed = the volume of the earth dug out
4046(h)=3080m^3
h=0.7612'm
=76cm።።።።just like yemam.
(( I do for m.c.s 9B students "good luck") )
=3,080m^3
Area Of filed =100×42= 4200m^2
The area of the remaning part of the filed=the area of field - the area of well, so. 4200m^2 - 154m^2 (22/7×7×7)=4046m^2
The volume of the riseing filed = the volume of the earth dug out
4046(h)=3080m^3
h=0.7612'm
=76cm።።።።just like yemam.
(( I do for m.c.s 9B students "good luck") )
12 answers