P from Q is 66-54 = 12°
PR^2 = 80^2 + 100^2 - 2*80*100 cos54°
sinP/100 = sin54°/PR
Q is 80km from p. r is 100km from q an a bearing of 066° . Angle pqr equals 054°
Calculate the bearing of p from q
The distance pr correct to 2 d.p
The measurement of angle qpr to the nearest degree.
2 answers
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2 answers