Asked by Anish

Q.3 Three point charges are placed at the following points on x-axis: 3µC at x=0, -4µC at x=50cm and
-5µC at x=120cm. Calculate the force on -4µC charge.

Answers

Answered by Damon
At 50 the force on Q2 is to the left (attractive) from Q1 and to the left (repulsive) from Q3 so they add and are in the -x direction.
F = -k * 4µC [ 3µC/0.50^2 + 5µC/0.70^2 ]
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